Replies

1. 
   Luka_ | Jan 09, 2002 01:22pm | #1

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1. 
   Stan_Foster | Jan 09, 2002 02:30pm | #2

   *Mark: I would take a piece of paper and wrap it around the elliptical tube. Mark exactly this perimeter length. Divide this by "pi" which is 3.14159. This number is the diameter of your round pipe that you will need.

1. 
   Ken_Drake | Jan 09, 2002 02:58pm | #3

   *Stan,Good post. Simple and easy approach to get the answer.

1. 
   Art_B. | Jan 09, 2002 04:14pm | #4

   *Mehinks this got a lot of attention last year. Circ. of ellipse of axis a and b, approximately, is 2*pi*sqrt((a^2+b^2)/2); The exact solution = 4 * A* C, where C is an elliptical function (gotten from table of functions or use your Mathcad or MatLab program) with a table constant k = Sqrt(a^2-b^2)/a.Like Ken says, use Stan's method unless you like to use math for fun.

1. 
   mark_cadioli | Jan 09, 2002 11:34pm | #5

   *Thanks.....maths for fun???yeah right!simplicity for me thankyou..Stan, now why didn't I think of that?regardsmark