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We have an upcoming commercial job that has a interior curved wall, radius is 14′. We will be building & installing a band of windows 2′ high by 10′ long. The glass will be flat panels, 2′ long sections. The top & bottom jambs will be straight 3/4″ thick yellow birch. these segments will have to be mitered. Does anybody know the formula for figuring the miter cuts. Any other info. reguarding this topic would be appreciated.
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Dave,
Find the theoretical circumference based on the radius: 2 x Pi(3.14...) x radius(14') = 87.9'(=/-).
Divide this by the desired length of the window units at the point where the mitre is to intersect the radius (this will depend on how you are building them, whether the radius is taken to be at the outside face of the wall, inside face, centre, etc.). Say for example 2' exactly.
Divide this number into the total circumference to get the "approximate" number of mitres required to complete the circle (87.9 divided by 2 = 43.95). Round to the nearest whole number = 44. Now re-calculate the window unit length: 87.9 divided by 44 = 1.99' (=/-). If the window units lengths need to be a little bigger then use 43 as your "number of mitres", or 42 or whatever.
Divide the "number of mitres", 44, into 360 to get the mitre angle: 8.18 degrees (=/-).
Hope this helps,
Steven
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Dave, Is that 14' inside or outside radius? What is thickness of wall. If you would like, E-mail me with the info or fax it to me, I will lay it out in CAD and fax it back.
-Rob
*It would help me to get a fax of this too, please.Thanks.
*Right on, Steven! I was going to send the calculations for a polygon inscribed in a circle, with the vertices tangent to the circumference. I decided to wait & see what other posts appeared. You did a fine job.
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We have an upcoming commercial job that has a interior curved wall, radius is 14'. We will be building & installing a band of windows 2' high by 10' long. The glass will be flat panels, 2' long sections. The top & bottom jambs will be straight 3/4" thick yellow birch. these segments will have to be mitered. Does anybody know the formula for figuring the miter cuts. Any other info. reguarding this topic would be appreciated.